Bayes factor: Revision history

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15 November 2019

  • curprev 09:1209:12, 15 November 2019imported>Manudouz 15,187 bytes +15,187 It's not a typo, because: Pr(D | M1) / Pr(D | M2) = [ Pr(M1 | D) x P(D) / P(M1) ] / [ Pr(M2 | D) x P(D) / P(M2) ] = [ Pr(M1 | D) / P(M1) ] / [ Pr(M2 | D) / P(M2) ] = [ Pr(M1 | D) x P(M2) ] / [ P(M1) x Pr(M2 | D) ]